Math, asked by pkumari84322, 7 months ago


: The present age of father is four times the age of his son.
After 10 years, age of father will become three times the
age of his son. Find their present ages.​

Answers

Answered by susammavarghesen06
2

Answer:

Step-by-step explanation:

Let the present age of son be x.

Present age of father=4x.

Now,

Ten year hence his father age will be 3 times his son.

A/q

4x + 10 = 3(x + 10) \\ 4x + 10 = 3x + 30 \\ 4x - 3x = 30 - 10 \\ x = 20

So,

Son age is=20 years

And father age is=4×20=80 years

Answered by safwannaseem2006
1

Answer:

20

Step-by-steP

the fathers age ; 4x

the son age ; x

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

father present age is 80

and son present age 20

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