Question

The present age of father is four times the age of his son.After 10 years,age of father will become three times the age of his son.find the present age of father answere

Answer 1

Let present age of son be x.

Let present age of father be 4x.

After 10 years.

Age of son = x+10

Age of father = 4x+10

According to question

4x + 10 = 3(x+10)

4x + 10 = 3x+30

4x - 3x = 30 -10

x = 20

So, present age of son = x=20

And present age of father = 4x = 20×4 = 80
Hope it will help you

Answer 2

Answer:

Father is 80 years old and son is 20 years old.

Step-by-step explanation:

Given :

Present age of father = four times the age of his son

After 10 years = Father will become three times the age of his son

To find :

Present age of father

Solution :

$\textbf{\small{\underline{Let the present ages be - }}}$

• Son as x
• Father as 4x

$\textbf{\small{\underline{After 10 years - }}}$

• Son = (x + 10)
• Father = (4x + 10)

$\textbf{\small{\underline{According to the Question -}}}$

After 10 years = Father will become three times the age of his son

$\rm{\implies} \: (4x + 10) =3(x + 10) \\ \rm{\implies} \: 4x + 10 = 3x + 30 \\ \rm{\implies} \: 4x - 3x = 30 - 10 \\ \rm{\implies} \: x = 20$

Son's present age = 20 years

$\rule{300}{1.5}$

★ Value of 4x

$\rm{\implies} \: 4(20) \\ \rm{\implies} \: 80$

Father's age = 80 years old

$\therefore$ Father is 80 years old and son is 20 years old.