Question

The present age of father is thrice the age of his 2 children.after 5 years,his age will be twice the sum of ages of 2 children.find the present age of the Father. ​

Answer 1

here is your answer......

age of father = ∆

age of children = ¥

acc to question ;

∆ = 3(¥). ------ eq 1

after 5 years ..

∆ +5 = 2 (¥+5+5 ). because there are 2 children

...........eq 2

on putting the values of ∆ in eq 2 from eq 1

3¥ +5 = 2 (¥+10)

3¥ = 2¥+20-5

3¥-2¥ = 15

¥ = 15

......

put the values of ¥ in eq 1

∆ = 3 (15) = 45.....

father is 45 years old....

and sum of their children is 15 years

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