Math, asked by siddhithasale90, 4 months ago

The
present
age of Fatheris Four
times of his son. After 10 years age
of the Father will become three
times the age of his son Find their
present ages​

Answers

Answered by bhaskerkoti
3

Answer:

First let's look at the solution:

Let the present age of son be x

Then father's present age is 4x

Now,

According to question,

That is 10 years ago,

4x- 10 = 10 (x- 10)

4x -10=10x-100

100–10=10x-4x

90=6x

x=90/6

x=15

therefore,

Father=4x

=4*15

=60 years old

………………………

FOLLOW ME dear friend

HOPE IT HELPS

Answered by AashishWadhwani
0

Answer:

son's age = 20

Father's age = 80

Similar questions