Question

the present age of Hina's mother is four times that of her daughter after 15 year the sum of their ages will be 75 years find the present age of hina's and mother ages​

Answer 1

Answer:

Present:

let hina's age be x and her mother's be y

y=4x---------------(1)

after 15 years

hina=x+15

mother=y+15

x+15+y+15=75

x+y=75-30

x+y=45---------------(2)

substituting 1 in 2

x+4x=45

5x=45

x=9

hina's age = 9 years

mother's age=9×4= 36 years

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