Question

The present age of merra and her brother are in the
ratio 6.5. Four years ago, the
ratio of their ages was 4.3.
I Find their present age​

Answer 1

Given :

• Present age of Merra and her brother is in the ratio 6:5

• Four years ago,the ratio of their age was 4:3

To Find :

• Present age of Merra and her brother

Solution :

Let Merra's present age be 6x and his brother be 5x

4 years ago :

★ Merra's age = 6x - 4

★ Brother's age = 5x-4

According to the Question :

$\longrightarrow \sf \: \dfrac{6x - 4}{5x - 4} = \dfrac{4}{3}$

$\longrightarrow \sf \: 3(6x - 4) = 4(5x - 4)$

$\longrightarrow \sf \: 18x - 12 = 20x - 16$

$\longrightarrow \sf \: 18x - 20x = - 16 + 12$

$\longrightarrow \sf \: - 2x = - 4$

$\longrightarrow \sf \: x = \cancel\dfrac{ - 4}{ - 2}$

$\longrightarrow \sf \red{ x = 2}$

We've assumed the age of Merra and his brother as 6x and 5x. Let's find their present ages by putting x = 2

$\bigstar \boxed{ \purple{ \sf Merra's \: age = 6(2) = 12 \: years}}$

$\bigstar \boxed{ \purple{ \sf \: Brother's \: age = 5(2) = 10 \: years}}$

Answer 2

❥ANSWER :

Meera's present age is 12 years and her brother's present age is 10 years.

❥ EXPLANATION :

•Given :-

• Present age of merra and her brother are in the ratio 6:5.
• Four years ago, the ratio of their ages was 4.3.

•To find :

• Their present ages.

• Solution :

Let Meera's present age be 6x years and her brother's present age be 5x years.

★ 4 years ago,

☆Meera's age = (6x-4) years.

☆Her brother's age = (5x-4) years.

Four years ago, the ratio of their ages was 4.3.

According to the question,

$\sf{(6x-4):(5x-4)=4:3}$

$\implies\sf{\frac{6x-4}{5x-4}=\frac{4}{3}}$

$\implies\sf{20x-16=18x-12}$

$\implies\sf{20x -18x=16-12}$

$\implies\sf{2x=4}$

$\implies\sf{x=2}$

✞ Putting the value of x = 2 ✞

Meera's present age=6 × 2 = 12 years.

Her brother's present age=5×2 = 10 years.

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