Math, asked by ItzDeadDeal, 2 days ago

The present age of mother is 40 years and that of her daughter is 10 years.
(i) Find the ratio of present age of the mother to the present age of her daughter.
(ii) Find the ratio of age of the mother to the age of daughter, when daughter was 8 years old.
(iii) Find the ratio of age of mother after 10 years to the age of daughter after 10 years.

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Answers

Answered by wwwaniketshobha222
0

Answer:

1. ratio= 40:10

=4:1

2. when the daughter was 8 years old her mother was 38 years old

ratio=38:8

=19:4

3. age after 10 years

mother's age= 50 years

daughter's age= 20 years

ratio= 50:20

= 5:2

Step-by-step explanation:

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Answered by Nighted
4

 \rm Answer

Present age of mother = 40 years.

Present age of her daughter = 10 years.

Ratio of mother's present age to daughter's present age = 40/10 = 4 : 1

When the daughter was 8 years old (means 2 years ago) her mother's age would be 2 years less than that her present age so, she must be 38 years old.

Ratio of mother's age to daughter's age (2 years ago) = 38/8 = 19 : 4

After, 10 years daughter must be of 20 years while her mother must be of 50 years.

Ratio of mother's age to daughter's age (10 years later) = 50/20 = 5 : 2

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