Question

The present age of ramesh is 1/3 of his fathers age. After 9 years the age of ramesh will be 5/12 of his fathers age . Find present age of both .​

Answer 1

Answer:

Let the present age of Ramesh be x.

Present age of father = 3x

After 9 years,

Age of Ramesh = x + 9

Age of father = 3x + 9

According to Question,

x + 9 = (3x + 9) 5/12

12 (x + 9) = (3x + 9) 5

12x + 108 = 15x + 45

108 - 45 = 15x - 12x

63 = 3x

x = 63 ÷ 3

x = 21

Hence, present age of Ramesh = 21 years

Present age of father = 63 years

Answer 2

ANSWER :

Ramesh's present age is 21 years and his father's present age is 63 years.

EXPLANATION :

GIVEN :-

• The present age of ramesh is 1/3 of his fathers age.
• After 9 years the age of ramesh will be 5/12 of his fathers age .

TO FIND :-

• Present age of both.

SOLUTION :

Consider,

Father's present age = x years.

Ramesh's present age = y years.

According to the question,

$\sf{y=\frac{1}{3}x}$

$\implies\sf{y=\frac{x}{3}}$

$\implies\sf{x=3y...........(i)}$

★ After 9 years ,

Father's age = ( x +9) years.

Ramesh's age = (y+9) years.

According to the question,

$\sf{y+9 =\frac{5}{12}(x+9)}$

$\implies\sf{y+9=\frac{5(x+9)}{12}}$

$\implies\sf{y+9=\frac{5(3y+9)}{12}}$

$\implies\sf{12y+108=15y+45}$

$\implies\sf{12y-15y=45-108}$

$\implies\sf{-3y=-63}$

$\implies\sf{y=21}$

Ramesh's present age = 21 years.

† Putting y = 21 in eq(i) †

x = 3y

→ x = 3×21

→ x = 63

Father's present age = 63 years.

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