Question

The present age of Sahil’s mother is three times the present age of Sahil. After 5 years their ages

will add to 66 years. Find the present ages of Sahil.​

Answer 1

Answer:

Present age of Sahil = 14 years

Explanation:

Let present age of Sahil = x year

present age of Sahil’s mother = 3x years

After 5 years

Age of Sahil = (x + 5) year

Age of Sahil’s mother (3x + 5)

⇒ (x + 5) + (3x + 5) = 66

⇒ x + 3x + 5 + 5 = 66

⇒ 4x + 10 = 66

⇒ 4x = 66 - 10

⇒ x = 56 / 4

⇒ x = 14

Present age of Sahil = 14 years

Present age of Sahil’s mother = 3x years

3x = 3 × 14 = 42 years

Answer 2

Let Sahil and his mother's ages be x and y repectively.

Given

The present age of Sahil’s mother is three times the present age of Sahil.

$\implies y = 3x --(1)$

After 5 years their ages  will add to 66 years.

$\implies \bold{Sahil's \ age \ after \ 5 \ years} =x+5$

$\implies \bold{Sahil's \ mother's \ age \ after \ 5 \ years} =y+5$

$\implies x + 5 + y + 5 = 66$

$\implies x+y+10=66$

$\implies x + 3x + 10=66 \ (From \ 1)$

$\implies 4x+10=66$

$\implies 4x = 66-10$

$\implies 4 x= 56$

$\implies x = \dfrac{56}{4}$

$\implies x= 14$

$\boxed{\boxed{\bold{Therefore, \ Sahil \ is \ 14 \ years \ old}}}}}}$