Question

The present age of Soya’s father is three times his present age. After five years , the sum of their ages is 70 years. Find their present ages.

Answer 1

Answer:

Step-by-step explanation:

Let Soya's present age be x

According to the question His father's present age = 3x

Now after 5 yrs

Soya's age = x+5

His father's age =3x+5

According 2 the question

(x+5)+(3x+5)=70

4x+10=70

x=15

Therefore Soya's present age =15yrs

His father's present age = 3×15=45yrs

Answer 2

Answer:

Father is 45 years old and Soya is 15 years old.

Step-by-step explanation:

Given :

Soya’s father is = three times of Soya's present age

Sum of their ages after 5 years = 70

To find :

Their present ages

Solution :

Consider the present ages as -

• Soya = y
• Father = 3y

Ages 5 years later -

• Soya = y + 5
• Father = 3y + 5

According to the question,

The sum of their ages after 5 years is 70,

⇒ (y + 5) + (3y + 5) = 70

⇒ 4y + 10 = 70

⇒ 4y = 60

⇒ y = 60/4

⇒ y = 15

Soya is Presently 15 years old.

$\rule{300}{1.5}$

★ Father's age -

⇒ 3 × y

⇒ 3 × 15

⇒ 45

Father is presently 45 years old.

$\therefore$ Father is 45 years old and Soya is 15 years old.