Question

the present age of Srinu and Mohan are in the ratio of 7 :5, after 10 years their ratio of ages will be 9:7 . find their ages after 15 years .​

Answer 1

Answer                                                                  

Present Age of A =35

Present Age of B =25

Step-by-step explanation:

Let the Present ages ofA and B be 7x and 5x respectively.

After 10 years, their ages will be (7x +10) and (5x + 10)

Given

(7x +10) : (5x + 10) = 9 : 7

⇒7(7x + 10)= 9(5x + 10)    Product of extremes = Product of means

⇒49x+ 70= 45x + 90

⇒49x - 45x = 90-70

⇒4x= 20

⇒x=20/4

⇒x=5

∴Age of A = 7x = 7 x 5 =35

Age of B = 5x = 5 x 5 =25

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Step-by-step explanation:

Answer 2

Answer:

50 and 40

Step-by-step explanation:

Let the present ages of Srinu and Mohan be 7x and 5x.

After 10 years, so let's add 10 to each of their ages : 7x + 10 , 5x + 10

After 10 years, their age ratio will be- 9 : 7 ( it can also be written as $\frac{9}{7}$)

Equate both sides :

$\frac{7x + 10}{5x + 10}$ = $\frac{9}{7}$

(# Cross multiply)

7(7x +  10) = 9(5x + 10)

49x + 70 = 45x + 90

(# Take all the variable and constant values to separate sides)

49x - 45x = 90 - 70

(# Remember to change the signs while transposing)

4x = 20

x = $\frac{20}{4}$

x = 5

Now, they asked us to find their ages after 15 years, so their ages would be : present age + 15

Srinu's age after 15 years : 7x + 15 ⇒ 7(5) + 15 ⇒ 35 + 15 = 50

Mohan's age after 15 years : 5x + 15 ⇒ 5(5) + 15 ⇒ 25 + 15 = 40

∴ The ages of Srinu and Mohan after 15 years will be 50 and 40 respectively.

Hope it helps!