Question

the present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages​

Answer 1

Answer:

father's current age= 40 years

son's current age=10 years

Step-by-step explanation:

let son's age be(present)= a

father's age(present)= 4a.

son's age after 20 years= a+20

father's age after 20 years= 4a+20

as son's age is 2 times his father's age after 20 years

4a+20= 2(a+20)

4a+20= 2a+40

4a-2a= 40-20

2a=20

a=20/2

a=10

as son's current age is =a= 10

so, father's current age= 4a=10*4=40

HOPE IT HELPS!!!!!!!!

Answer 2

The present age of Son is 10 years and the present age of father is 40 years

Step-by-step explanation:

Solution :

Let,

The present age of Son = a

The present age of Father = 4a

After 20 years,

The age of Son = a + 20

The age of Father = 4a + 20

Also,

The age of Father will be twice the age of the Son

So,

⇒ 2 (a + 20) = 4a + 20

⇒ 2a + 40 = 4a + 20

⇒ 40 - 20 = 4a - 2a

⇒ 20 = 2a

⇒ a = 20 / 2

⇒ a = 10

The present age of Son = 10 years

The present age of Father = 4a

⇒ 4a

⇒ 4 (10)

⇒ 40

The present age of Father = 40 years

∴ The present age of Son is 10 years and the present age of Father is 40 years