The present age of three persons are in proportions 5:6:7.Five years ago,the sum of their ages was 39.Find the sum of their ages (in years)
Answers
the present ages of three persons are in proportion 5:6 :7. five years ago the sum of their ages was 39. find the sum of their present ages in years
The sum of the present ages is 54
GIVEN
The ratio of present age = 5:6:7
Sum of ages 5 years ago = 39
TO FIND
Sum of the present age.
SOLUTION
We can simply solve the above problem as follows -
It is given,
The ratio of present age = 5:6:7
Let the common multiple be x
Age of 1st person = 5x
Age of second person = 6x
Age or third person = 7x
Sum of age 5 years ago = 39
(5x-5)+(6x-5)+(7x-5) = 39
18x - 15 = 39
18x = 39+15
18x = 54
x = 54/18 = 3
So,
Age of 1st person = 5 × 3 = 15 years
Age of second person = 6 × 3 = 18 years
Age or third person = 7 ×3 = 21 years
the sum of ages = 15+18+21 = 54
Hence, The sum of the present ages is 54
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