Math, asked by Shreyes57651, 1 month ago

the present age of three persons are in the ratio 4:7:9eight years ago the sum of their ages was 56 Find their present ages

Answers

Answered by harshadkmh11
0

Answer:

16,28,36

Step-by-step explanation:

4:7:9=>4x+7x+9x=56+3×8=80=>x=4

so ages are 16,28,36

Answered by ameyashelardav
0

Let their ages be 4x, 7x and 9x

Sum of their age ratio EIGHT YEARS AGO = (4x-8),(7x-8) and (9x-8).

(4x-8)+(7x-8)+(9x-8)=56

[(4x+7x+9x)+[(-8)+(-8)+(-8)]]=56

20x - 24 = 56

20x = 56+24

20x = 80

x = 80/20

= 4

Hence, their present ages are as follows

16 years (4 X 4)

28 years (4 X 7)

36 years (4 X 9)

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