the present age of three persons are in the ratio 4:7:9eight years ago the sum of their ages was 56 Find their present ages
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Answered by
0
Answer:
16,28,36
Step-by-step explanation:
4:7:9=>4x+7x+9x=56+3×8=80=>x=4
so ages are 16,28,36
Answered by
0
Let their ages be 4x, 7x and 9x
Sum of their age ratio EIGHT YEARS AGO = (4x-8),(7x-8) and (9x-8).
(4x-8)+(7x-8)+(9x-8)=56
[(4x+7x+9x)+[(-8)+(-8)+(-8)]]=56
20x - 24 = 56
20x = 56+24
20x = 80
x = 80/20
= 4
Hence, their present ages are as follows
16 years (4 X 4)
28 years (4 X 7)
36 years (4 X 9)
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