The present age of vinodbhai is three times more than the age of his son. Before ten years his age was five times more than the age of his son. Find the age of both
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Answered by
3
heya mate
this is priya
for any queries u can inbox me
brainly star
well here is your answer
let
the present age of son to be X
then the present age of Vinodhbai is 3X
let
10 years ago age of
son be X-10
Vinodhbai be 3X - 10
ATQ
(X - 10 ) 5 = 3X - 10
5X - 50 = 3X - 10
5X - 3X = 50 - 10
2X = 40
X = 20
therefore, present age of son is x = 20yrs
present age of Vinodbhai is 3x = 3×20 = 60yrs
^_^
this is priya
for any queries u can inbox me
brainly star
well here is your answer
let
the present age of son to be X
then the present age of Vinodhbai is 3X
let
10 years ago age of
son be X-10
Vinodhbai be 3X - 10
ATQ
(X - 10 ) 5 = 3X - 10
5X - 50 = 3X - 10
5X - 3X = 50 - 10
2X = 40
X = 20
therefore, present age of son is x = 20yrs
present age of Vinodbhai is 3x = 3×20 = 60yrs
^_^
Answered by
1
3x-10=5(x-10)
3x-10=5x-50
3x-5x=-50+10
-2x=-40
x=-40/-2=20
So, his son's age=x=20years
Therefore, Vinod bhai present age=3x
3×20=60years.
Hope it helps you...
3x-10=5x-50
3x-5x=-50+10
-2x=-40
x=-40/-2=20
So, his son's age=x=20years
Therefore, Vinod bhai present age=3x
3×20=60years.
Hope it helps you...
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