Math, asked by Ajaryajoshi, 1 year ago

The present age of vinodbhai is three times more than the age of his son. Before ten years his age was five times more than the age of his son. Find the age of both

Answers

Answered by Anonymous
3
heya mate

this is priya

for any queries u can inbox me

brainly star

well here is your answer


let
the present age of son to be X
then the present age of Vinodhbai is 3X

let

10 years ago age of
son be X-10
Vinodhbai be 3X - 10

ATQ

(X - 10 ) 5 = 3X - 10

5X - 50 = 3X - 10

5X - 3X = 50 - 10

2X = 40

X = 20

therefore, present age of son is x = 20yrs

present age of Vinodbhai is 3x = 3×20 = 60yrs

^_^
Answered by Gauranshi1
1
3x-10=5(x-10)
3x-10=5x-50
3x-5x=-50+10
-2x=-40
x=-40/-2=20
So, his son's age=x=20years
Therefore, Vinod bhai present age=3x
3×20=60years.
Hope it helps you...
Similar questions