The present age s of a and b are in the rato 7:5 ten years later their ages will be in the ratio 9:7 find present ages
Answers
Answer :-
Let present age of "A" be 7x , and
Present age of "B" be 5x.
After 10 years ,
Age of A = 10 + 7x
Age of B = 10 + 5x
According to question :-
=) 10 + 7x = 9x
=) 10 = 9x - 7x
=) 10 = 2x
=) x = 5
Also, 10 + 5x = 7x
=) 10 = 7x - 5x
=) 10 = 2x
=) x = 5
So, the value of x is 5.
Present age of A = 7x
= 7 × 5 = 35
= 35 Years
Present age of B = 5x
= 5 × 5 = 25
= 25 Years
So, the present ages of A & B are 35 & 25 years.
Answer :- The present age of A = 35 and B = 25 year.
Explanation :-
Let the present age of A and B be 7x and 5x respectively.
According to the given condition we get,
10 year later their age ratio is 9:7
Therefore,
The age of A will be
10 + 7x = 9x ---(1)
The age of B will be
10 + 5x = 7x ---(2)
Solving equation (1)
10 + 7x = 9x
10 = 9x - 7x
10 = 2x
x = 10/2
x = 5
Solving equation (2)
10 + 5x = 7x
10 = 7x - 5x
10 = 2x
x = 10/2
x = 5
Substituting the value of x = 5 to get the present age of A and B
The present age of A = 7x
7(5)
35 years
The present age of B = 5x
5(5)
25 years
Therefore, The present age of A = 35 and B = 25 year.