The present ages of a and b are in the ratio 6;4 five years ago their ages were in the ratio 5:3 find their present age?
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Let the present ages of a and b be in the ratio 6x : 4x
Before 5 years their ages would have been 6x - 5 and 4x - 5. This was in the ratio 5 : 3.
=> 6x - 5 : 4x - 5 :: 5 : 3
Product of Means = Product of Extremes
=> ( 6x - 5 ) ( 3 ) = ( 4x - 5 ) ( 5 )
=> 18x - 15 = 20x - 25
=> 25 - 15 = 20x - 18x
=> 10 = 2x
=> x = 10 / 2 = 5
Hence their present ages are:
a = 6x = 6 * 5 = 30 years
b = 4x = 4 * 5 = 20 years
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