Question

The present ages of A and B are in the ratio 7:5. Ten years later, their ages will be in the ratio 9:7. Find their present ages.​

Answer 1

Answer:

Let the present age of A= 7x years

The present age of B= 5x years

After 10 years, their ages will be

A=7x+10 years and

B=5x+10 years

The ratio of their ages after 10 years is 9:7.

∴

5x+10

7x+10

=

7

9

⇒49x+70=45x+90

⇒49x−45x=90−70

⇒4x=20

⇒x=5

∴ Present age of A= 7×5=35 years and present

age of B= 5×5=25 years.

Answer 2

Answer:

wrong questions

Step-by-step explanation:

Let A's present age be= 7x

Let B's present age be = 5x

therefore,7x/5x+10/10=9/7

therefore,9(7x+10)=7(5x+10)

56x+90=35x+70