Question

. The present ages of a father and son is 13:11; 9 years ago
the ratio of their ages was 5:4. Find the difference in the
father's present age and the son's age five years later.​

Answer 1

SOLUTION

GIVEN

• The present ages of a father and son is 13 : 11

• 9 years ago the ratio of their ages was 5 : 4

TO DETERMINE

The difference in the father's present age and the son's age five years later.

EVALUATION

Here it is given that 9 years ago the ratio of their ages was 5:4.

Let 9 years ago father age was 5x years and son's age was 4x years

So present age of father = 5x + 9 years

Present age of son = 4x + 9 years

Now it is also stated that the present ages of a father and son is 13:11

So by the given condition

$\displaystyle \sf{ \frac{5x + 9}{4x + 9} = \frac{13}{11} }$

$\displaystyle \sf{ \implies \: 55x + 99 = 52x + 117 }$

$\displaystyle \sf{ \implies \: 3x = 18 }$

$\displaystyle \sf{ \implies \: x = 6 }$

Present age of father = 39 years

Present age of son = 33 years

Now five years later

Age of son = 33 + 5 = 38 years

Hence the required difference of father's present age and the son's age five years later

= ( 39 - 38 ) years

= 1 year

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. 6 years ago, Mahima mother age was 3 times as old as Mahima. After 5 years, she will be twice as old as Mahima. Present ...

https://brainly.in/question/36116267

2. 5 years ago, Bharti's mother was 3 times as. old as. Bharti . After 6 years she will be twice as old as Bharti Present...

https://brainly.in/question/36004926