Math, asked by Anonymous, 10 months ago

The present ages of Amayra and Deepika are in the ratio 11:8. 8 years later the sum of their ages will be 54 years. What are their present ages?​

Answers

Answered by Aryankumar785
0

Answer:

Ratio given = 11:8

Let Rohan's current  age be = 11x

hence, Mayank's current age = 8x

Acc to the question ,

(11x + 8) + (8x + 8) = 54

11x + 8 + 8x + 8 = 54

19x + 16 = 54

19x = 54 - 16

19x = 38

x = 38/19

x = 2

Hence,

Rohan's present age = 11x =11×2=22

Mayank's present age = 8x = 8×2= 16

Answered by vaibhavshukla97
0

Step-by-step explanation:

let,

the present age of amayra=11x

present age of deepika=8x

ACCORDING TO QUESTION

(11x+8)+(8x+8)=54

11x+8+8x+8=54

19x+16=54

19x=54-16

19x=38

x=38/19

x=2

since present age of amayra=11*2=22year

present age of deepika=8*2=16

hope this helps you

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