The present ages of Mr. Sen and his son are in the ratio 17:9. If the ratio of there ages,9 years ago was 7:3, then find their present ages.
Answers
Answer:
51 and 27 years
Step-by-step explanation:
Let the present ages be 17x and 9x.
Then, the ratio of ages 9 years ago would be (17x-9)/(9x-9)
Solving, the value of x will be 3.
So, the present ages are 17*x that is 51 years
and 9*x that is 27 years.
Answer:
Mr. Sen's Age = 51 years
His Son's Age = 27 years
Step-by-step explanation:
Let the ages of Mr. Sen and his son be 17x and 9x
As given in the question, their ages 9 years ago was in the ratio 7:3.
This can be rewritten as,
17x - 9 7
--------- = --------
9x - 9 3
By cross-multiplying, we get ;
3 (17x-9) = 7 (9x-9)
By distributing 3 and 7 we get;
(3*17x) - (3*9) = (7*9x) - (7*9)
= 51x - 27 = 63x - 63
By shifting constants to one side and variables to the other side, we get,
63 - 27 = 63x - 51x
36 = 12x
So, x = 36
------
12
= 3
Answer: -
Mr. Sen's age = 17*3 = 51 years
His Son's age = 9*3 = 27 years
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