Math, asked by DarkOwl, 11 months ago

The present ages of Mr. Sen and his son are in the ratio 17:9. If the ratio of there ages,9 years ago was 7:3, then find their present ages.

Answers

Answered by shiwanigupta97
1

Answer:

51 and 27 years

Step-by-step explanation:

Let the present ages be 17x and 9x.

Then, the ratio of ages 9 years ago would be (17x-9)/(9x-9)

Solving, the value of x will be 3.

So, the present ages are 17*x that is 51 years

and 9*x that is 27 years.

Attachments:
Answered by dasarigopikrishna07
2

Answer:

Mr. Sen's Age = 51 years

His Son's Age = 27 years

Step-by-step explanation:

Let the ages of Mr. Sen and his son be 17x and 9x

As given in the question, their ages 9 years ago was in the ratio 7:3.

This can be rewritten as,

17x - 9          7

---------  =  --------

9x - 9          3

By cross-multiplying, we get ;

3 (17x-9) = 7 (9x-9)

By distributing 3 and 7 we get;

(3*17x) - (3*9) = (7*9x) - (7*9)

= 51x - 27  = 63x - 63

By shifting constants to one side and variables to the other side, we get,

63 - 27 = 63x - 51x

36 = 12x

So, x = 36

          ------

            12

= 3

Answer: -

Mr. Sen's age = 17*3 = 51 years

His Son's age = 9*3 = 27 years                  

Hope this solved your doubt.

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