Math, asked by avinash0852, 1 year ago

The present ages of Mr.Sen and his son are in the ratio17:9 . If the ratio of their ages , 9 years ago was 7:3 , then find their present ages .

Answers

Answered by Panzer786
104
Hello !!


Let present age of sen and his son be 17X and 9X .


Before 9 years age of sen = ( 17X - 9 ) years.


Before 9 years age of his son = ( 9X - 9) years.



According to question,



17X-9 : 9X - 9 = 7 : 3



3 ( 17X - 9 ) = 7 ( 9X - 9 )


51X - 27 = 63X - 63

51X - 63X = -63 + 27



-12X = -36



X = -36/-12 = 3


Present age of sen = 17X = 17 × 3 = 51 years.


And,


Present age of his son = 9X = 9 × 3 = 27 years.



avinash0852: thank you
Answered by simahaldet912
7

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