The present ages of rohit and mayank are in the ratio 11:8.8years later the sum of their ages will be 54 years what is present age
Answers
Answered by
105
Q. The present age of rohit and mayank are in the ratio 11:8 . 8years later the sum of their ages will be 54 years. What is their present age?
Solution :
Given,
age ratio of rohit and mayank = 11:8
Let,
rohit age = 11x years
mayank age = 8x years
[ According to the question ]
After 8 years sum of their ages will be 54
So,
rohit age after 8 years = (11x+8) years
mayank age after 8 years = (8x+8) years
Now,
(11x+8) + (8x+8) = 54
=> 11x + 8x + 8 + 8 = 54
=> 19x + 16 = 54
=> 19x = 54 - 16
=> 19x = 38
=> x = 38/19
=> x = 2
Hence, value of x = 2
Therefore,
rohit age = (11x + 8) = (11*2 + 8) = 30 years
mayank age = (8x + 8) = (8*2 + 8) = 24 years
Hence, the present age of
rohit = 30 years
and mayank = 24 years.
Solution :
Given,
age ratio of rohit and mayank = 11:8
Let,
rohit age = 11x years
mayank age = 8x years
[ According to the question ]
After 8 years sum of their ages will be 54
So,
rohit age after 8 years = (11x+8) years
mayank age after 8 years = (8x+8) years
Now,
(11x+8) + (8x+8) = 54
=> 11x + 8x + 8 + 8 = 54
=> 19x + 16 = 54
=> 19x = 54 - 16
=> 19x = 38
=> x = 38/19
=> x = 2
Hence, value of x = 2
Therefore,
rohit age = (11x + 8) = (11*2 + 8) = 30 years
mayank age = (8x + 8) = (8*2 + 8) = 24 years
Hence, the present age of
rohit = 30 years
and mayank = 24 years.
Answered by
51
Ratio given = 11:8
Let Rohan's current age be = 11x
hence, Mayank's current age = 8x
Acc to the question ,
(11x + 8) + (8x + 8) = 54
11x + 8 + 8x + 8 = 54
19x + 16 = 54
19x = 54 - 16
19x = 38
x = 38/19
x = 2
Hence,
Rohan's present age = 11x =11×2=22
Mayank's present age = 8x = 8×2= 16
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