Math, asked by manishapatel8158, 22 days ago

The present ages of Rohit and Mayank are in the ratio 11 : 8. 8 years later the sum of their ages will be 54 years. What are their present ages?​

Answers

Answered by itzEllie
2

Answer

Ratio in the present ages of Rohit and Mayank =11:8

Let age of Rohit 11x, then that of Mayank =8x8 years

hence, their ages will beAge of Rohit =11x+8 yearsand age of Mayank =8x+8 yearsand the ratio of their ages after 8 years =5:48x+811x+8=45⇒ 44x+32=40x+40⇒ 44x−40x=40−32⇒ 4x=8⇒ x=2Present age of Rohit =11x=11×2=22 yearsand age of Mayank =8x=8×2=16 years.

Answered by Missincridedible
79

  • Present age of Rohit = 22 years
  • Present age of Mayank = 16 years

Step-by-step explanation:

Given :-

The present ages of Rohit and Mayank are in the ratio 11 : 8. 8 years later the sum of their ages will be 54 years.

To Find :-

What are their present ages?

Let :-

Present age of Rohit = 11x

Present age of Mayank = 8x

Ages after 8 years,

Rohit age = 11x + 8

Mayank age = 8x + 8

By the question,

(11x + 8) + (8x + 8) = 54

➟ 11x + 8 + 8x + 8 = 54

➟ 19x + 16 = 54

➟ 19x = 54 - 16

➟ 19x = 38

➟ x = 2

Hence,

  • Present age of Rohit = 11x = 11 × 2 = 22 years
  • Present age of Mayank = 8x = 8 × 2 = 16 years
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