the present ages of sunita and smita are in the ratio 3:5.if sunita had been 4 years ol why is older and Smitha 4 years younger the age of Sunita would have been 3 times the age of smita find their present ages
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Hi friend
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Your answer
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SOLVING (BY METHOD OF SUBSTITUTION)
------------------------------------------------------------------
Let Sunita's age be x and Smita's age be y.
According to the question,
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Equations
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x/y = 3/5....... (i)
x + 4 = 3(y - 4)........ (ii)
From equation (i), we get,
----------------------------------------
x/y = 3/5
=> 3y = 5x
=> y = 5x/3...... (iii)
Now,
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From equation (iii), we get,
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x + 4 = 3(y - 4)
=> x + 4 = 3y - 12
=> x - 3y = - 12 - 4
=> x - (5x/3 × 3) = - 16 [ From (iii)]
=> x - 5x = - 16
=> - 4x = - 16
=> 4x = 16
=> x = 16/4
=> x = 4
Therefore,
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Sunita's age = x = 4 years
Smita's age = 5x/3 = (5× 4)/3 years = 20/3 years
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
---------------
Your answer
-----------------------
SOLVING (BY METHOD OF SUBSTITUTION)
------------------------------------------------------------------
Let Sunita's age be x and Smita's age be y.
According to the question,
-------------------------------------------
Equations
-------------------
x/y = 3/5....... (i)
x + 4 = 3(y - 4)........ (ii)
From equation (i), we get,
----------------------------------------
x/y = 3/5
=> 3y = 5x
=> y = 5x/3...... (iii)
Now,
-----------
From equation (iii), we get,
-------------------------------------------
x + 4 = 3(y - 4)
=> x + 4 = 3y - 12
=> x - 3y = - 12 - 4
=> x - (5x/3 × 3) = - 16 [ From (iii)]
=> x - 5x = - 16
=> - 4x = - 16
=> 4x = 16
=> x = 16/4
=> x = 4
Therefore,
-------------------
Sunita's age = x = 4 years
Smita's age = 5x/3 = (5× 4)/3 years = 20/3 years
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
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