The present ages of three people are in ratio 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages
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Answered by
10
4x-8+7x-8+9x-8=56
20x=56+24
x=80/20=4
4X=16
7X=28
9X=36
20x=56+24
x=80/20=4
4X=16
7X=28
9X=36
Answered by
5
here is your answer
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RaoVishesh:
thanx for choosing brainliest
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