Question

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

Answer 1

Given,

Present ages of three persons = 4:7:9

Let the present ages be 4x, 7x and 9x in a respectively years.

So we have to find 8 years ago,Equation be like:-

=> (4x-8)+(7x-8)+(9x-8)= 56
=> 4x -8+7x-8+9x-8=56.
=>4x+7x+9x=56+8+8+8(by transferring)
=>20x=80
=>x=80/20
=>x=4


So,for calculating the current age we have to put the value of the x

So we get,

(4x:7x:9x)= we get the ratio as 16:28:36

Answer 2

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

20x = 80

x = 4.

Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.