Question

The present ages of three persons in proportions 4 is to 7 is to 9 8 years ago the sum of their ages was 56 find their present ages in the years

Answer 1

Answer:

Step-by-step explanation:

Let the present ages of the three persons be 4x, 7x and 9x.

So, their ages 8 years ago were 4x-8, 7x-8 and 9x-8.

According to given condition,

4x-8+7x-8+9x-8 = 56

20x -24 = 56

20x = 80

x = 4

So, present ages of three persons are

4x = 16 years

7x = 28 years

9x = 36 years