Question

the present of a son is half the present age of his father.ten years ago the father was thrice as old as his son. what are their present age.



P.S. please give the working also

Answer 1

Step-by-step explanation:

$let \: present \: age \: of \: son \: be \: x \\ and \: present \: age \: of \: father \: be \: y$

$atq = > \\ 2x = y \\ 2x - y = 0.............(1) \\ \\ (x - 10)3 = y - 10 \\ 3x - 30 - y + 10 = 0 \\ 3x - y - 20 = 0........(2) \\ \\ eq \: (2) - (1) = > \\ \\ 3x - y = 20 \\ 2x - y = 0 \\ - \: \: \: \: + \: \: \: \: \: - \\ \\ x = 20 \\ \\ 2x - y = 0 \\ put \: x = 20 \\ 40 - y = 0 \\ y = 40 \\ \\ therefore \: sons \: age \: is \: 20 \: and \: fathers \: age \: is \: 40 \\ \\ hope \: it \: helps \: uh..$