Question

The present population of a city is 3,02,500. If the population increases by 10 percent every year, what was the population of the city two years ago

Answer 1

Answer:

Population after 2 years = 366025

Step-by-step explanation:

Population after 2 years = 302500 * (110/100) * (110/100) = 366025

Answer 2

Present population = 302500
Increases rate = 10% p.a.
Three years ago population =
302500 ( 1 - 10/100)^2
302500(1-1/10)^2
302500* 9/10*9/10
3025*9*9
245025

Three years ago population was 245025

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