Question

THE PRESENT POPULATION OF A CITY IS 62740.TF THE POPULATION INCREASE S AT THE RATE OF 5%@OF EACH YEAR. WHAT WILL BE THE POPULATION OF THE CITY IN THE NEXT YEAR?​

Answer 1

Given:

• The present population of a city is 62740
• The rate of growth of the population in each year is 5%

So, we have to find the population of the city in the next year.

Time = 1 year

We know that,

When the population growth is constant for all the given number of year, then the population after n years will be,

$\boxed{\red{P(1+\frac{R}{100})^{n}}}$

So,

Population in next year, i.e. population after 1 year will be,

$= 62740(1+\frac{5}{100})^{1}$

$= 62740 \times (1+\frac{1}{20})$

$= 62740 \times (\frac{20+1}{20})$

$= 6274\not0 \times (\frac{21}{2\not0})$

$= 6274 \times (\frac{21}{2})$

= 65877

Hence,

The population of the city in the next year(after one year) when the rate of growth per annum is 5% = 65877.

Answer 2

Answer:

125.48

Step-by-step explanation:

62740/5x100=62740/500=125.48