Question

the present population of a town is 15625 if the population increases at the rate of 4% every year what will be the increase in the population in next 3 years

Answer 1

Answer:

$\red {Increase \: in \:the \: population \: in}$

$\red { next \:3 \: years} \green{= 1951 }$

Step-by-step explanation:

$Given \: present \: population \:of \: a \:town \\(x)= 15625$

$Rate \: of \: increase (r) = 4\% \:p.a$

$Time (n) = 3$

$Population \: after \: end \: of \: 3^{rd} \: year \\= x\left( 1+\frac{r}{100}\right)^{n}$

$= 15625\left( 1 + \frac{4}{100}\right)^{3}$

$= 15625\left( 1+ \frac{1}{25}\right)^{3}$

$= 15625\left( \frac{25+1}{25}\right)^{3}$

$= 15625\left(\frac{26}{25}\right)^{3}$

$= 15625 \times \frac{26}{25}\times \frac{26}{25}\times \frac{26}{25}$

$= 17576$

$Increase \: in \:the \: population \: in \:next \\3 \: years = 17576 - 15625 = 1951$

Therefore.,

$\red {Increase \: in \:the \: population \: in}$

$\red { next \:3 \: years} \green{= 1951 }$

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Answer 2

Answer:

Step-by-step explanation: