Question

The pressure exercted by weight of a cubical block of side three cm on the surface is 5pa . claculate the weight of the block force equal weight

Answer 1

Pressure is equal to=Force per area exerted by an object.

P=F/A

Area =(3/100)^2

0.03×0.03=0.0009m2

F=0.0009×5=0.0045N

Answer 2

Given Side of cubical box = 3cm = 3/100m = 0.03m .

Area = side² = 9/10000= 0.0009 m² = 9/10^4 m²

Pressure = 5Pa .

We know that,
Pressure = Force / Area .

5Pa = F / 9×${10}^{ - 4}$

5 × 9 × ${10}^{ - 4}$= F.

Therefore, Force exerted on the box is 45*${10}^{ - 4}$N