Physics, asked by reenajayant2006, 11 months ago

the pressure exerted by 50 kg(g=10 m/s² ) on an area of cross section of 2 m² is:​

Answers

Answered by Anonymous
17

\text{Given the mass of the object is 50kg}

Area\:of the\:cross\:section = 2m^{2}

 Acceleration\:due\:to\:gravity = 10m/s^{2}

\bold\red{\boxed{Thrust = mass \times acceleration}}

\bold\blue{\boxed{Thrust = 50kg \times 10m/s^{2}}}

\bold\blue{\boxed{Thrust = 500 N}}

______________________________________

\bold\red{\boxed{Pressure = \dfrac{Thrust}{Area}}}

\bold\blue{\boxed{Pressure = \dfrac{500N}{2m^{2}}}}

\bold\blue{\boxed{Pressure = 250N m^{2}}}

Answered by smartydude
0

Explanation:

Given the mass of the object is 50kg

Area\:of the\:cross\:section = 2m^{2}Areaofthecrosssection=2m

2

Acceleration\:due\:to\:gravity = 10m/s^{2}Accelerationduetogravity=10m/s

2

\bold\red{\boxed{Thrust = mass \times acceleration}}

Thrust=mass×acceleration

\bold\blue{\boxed{Thrust = 50kg \times 10m/s^{2}}}

Thrust=50kg×10m/s

2

\bold\blue{\boxed{Thrust = 500 N}}

Thrust=500N

______________________________________

\bold\red{\boxed{Pressure = \dfrac{Thrust}{Area}}}

Pressure=

Area

Thrust

\bold\blue{\boxed{Pressure = \dfrac{500N}{2m^{2}}}}

Pressure=

2m

2

500N

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