the pressure exerted by a cube of side 0.03mon a surface is 10pa. calculate the thurst exerted by the cube
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Heya.
This is your answer.
GIVEN :-
Side of cube = 0.03 m
Hence, area = 0.03 X 0.03 = 0.0009 m². (as area of cube is side²)
Pressure = 10 Pa.
As we know that thrust is force acting per unit area.
So, thrust = force.
and force = pressure X area
So,
= 10 X 0.0009
= 0.009 Pa.
Hence, the thrust exerted by the box is 0.009 Pa.
Hope it helps
This is your answer.
GIVEN :-
Side of cube = 0.03 m
Hence, area = 0.03 X 0.03 = 0.0009 m². (as area of cube is side²)
Pressure = 10 Pa.
As we know that thrust is force acting per unit area.
So, thrust = force.
and force = pressure X area
So,
= 10 X 0.0009
= 0.009 Pa.
Hence, the thrust exerted by the box is 0.009 Pa.
Hope it helps
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