Question

The pressure exerted by a wooden box of 162 kgf and a base of 30cm × 30cm. 1 kgf = 10N

Answer 1

Pressure (P) = $\frac{F}{A}$ where F is force and A is contact area.

If the wooden object is kept such that it's base (30cm x 30cm) is the contact area (touching ground) then,

First of all, area (A) must be in m $^{2}$

In the question it's given that 1kg = 10N,

∴ F = 10$\frac{N}{kg}$ * 162kg = 1620 Newtons

Also, A = 0.3m x 0.3m = 0.09$m^{2}$  {1m = 100cm, ∴ 30cm = 0.3m}

∴ P = $\frac {1620}{0.09}$·$kg$·$m^{-2}$

P = 18000 Pascals