Question

the pressure exerted by the weight of a cubical block of side 3 cm on the surface area is 5 Pa .calculate the weight of the block.

Answer 1

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Formula to be used
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$\bf \: = > force(f) = {pressure} \times {area} = {p} \times {a}$
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Given,
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=> Surface area (a) =(3×3) cm²

$\bf \: = \frac{9}{100 \times 100} = 0.0009 \: {m}^{2}$

=> pressure (p) = 5 Pa

So,

$\bf \: force \: = {p} \times {a} = 5 \times 0.0009 = 0.0045 \: \: newton$
So..
The required weight (f) = 0.0045 newtons

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Answer 2

Answer:

Answer I 0.0045 newtons