the pressure exerted on a table , when a cube of side 10 cm and mass 5 kg is kept on it , will be...?
Answer in kPa
Answers
Answered by
6
pressure = force/ area = weight / area
= (5× 10) N / (0.1 m)^2
= 50 N / 0.01 m^2
= 5000 Pa
= 5 × 10^3 Pa
= 5 kPa
= (5× 10) N / (0.1 m)^2
= 50 N / 0.01 m^2
= 5000 Pa
= 5 × 10^3 Pa
= 5 kPa
deepanshi9:
kg is not converted into g. answer will be 5 kpas
its 5 kg not 50 kg
thanks
Thanks a lot!
Answered by
0
Answer:
Explanatipressure = force/ area = weight / area
= (5× 10) N / (0.1 m)^2
= 50 N / 0.01 m^2
= 5000 Pa
= 5 × 10^3 Pa
= 5 kPa
Similar questions