the pressure exerted on a table , when a cube of side 10 cm and mass 5 kg is kept on it , will be
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44
Surface area of one face of the cube = 10*10 cm² = 0.01 meter²
weight of the cube = 5 kg = mass * gravity = 5kg * 10 metres/sec² = 50 newtons
pressure or stress exerted by the cube on the table = force / area through which the force acts
= weight / surface area of cube
= 50 newtons / 0.01 meter² = 5, 000 N/m² or Pa.
weight of the cube = 5 kg = mass * gravity = 5kg * 10 metres/sec² = 50 newtons
pressure or stress exerted by the cube on the table = force / area through which the force acts
= weight / surface area of cube
= 50 newtons / 0.01 meter² = 5, 000 N/m² or Pa.
Answered by
7
Answer:
Explanation:
Surface area of one face of the cube = 10*10 cm² = 0.01 meter²
weight of the cube = 5 kg = mass * gravity = 5kg * 10 metres/sec² = 50 newtons
pressure or stress exerted by the cube on the table = force / area through which the force acts
= weight / surface area of cube
= 50 newtons / 0.01 meter² = 5, 000 N/m² or Pa.
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