The pressure in a bicycle tire is 1.34 atm at 33.0°C. At what temperature will the pressure inside the tire be 1.60 atm if volume is constant?
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Answer: Since the pressure and temperature is given and volume is constant, we use Charles' law
P1V1/T1 = P2V2/T2
Hence, T2 = P2T1/P1
T = 1.60 atm x (273.15 K + 33)/1.34 atm
T = 365.5 K
Explanation:
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