The pressure in water pipe at the ground floor of a building is 1.5 x 105 Pa, whereas the pressure on fifth floor is 2 x 104 Pa. Calculate the height of the fifth floor. (Take g = 10 ms-2)
Answers
Answered by
4
Given :-
Pressure in water pipe at the ground floor = 1.5 × 10⁵ Pa
Pressure in water pipe on the fifth floor = 2 × 10⁴ Pa
To Find :-
The height of the fifth floor.
Analysis :-
Firstly find the height of the building by substituting the given values in the question.
Then you can easily find the height of the fifth floor using the formula of pressure exerted accordingly.
Solution :-
We know that,
p = Pressure
d = Density
g = Gravity
h = Height
Using the formula,
\underline{\boxed{\sf Pressure=Height \times Density \times Gravity}}
Pressure=Height×Density×Gravity
Given that,
Pressure (p) = 1.5 × 10⁵ Pa
Density (d) = 1000 kg/m³
Gravity (g) = 10 m/s
Substituting their values,
\sf 1.5 \times 10^5=h \times 1000 \times 101.5×10
5
=h×1000×10
\sf h=\dfrac{1.5 \times 10^5}{10 \times 1000}h=
10×1000
1.5×10
5
\sf h=5 \ mh=5 m
Therefore, the height of the building is 15 m.
Using the formula,
\underline{\boxed{\sf Pressure=Height \times Density \times Gravity}}
Pressure=Height×Density×Gravity
Given that,
Pressure (p) = 2 × 10⁵ Pa
Density (d) = 1000 kg/m³
Gravity (g) = 10 m/s
Substituting their values,
\sf 2 \times 10^4=h \times 1000 \times 102×10
4
=h×1000×10
\sf h=\dfrac{2 \times 10^4}{10 \times 1000}h=
10×1000
2×10
4
\sf h=2 \ mh=2 m
Therefore, the height from the tank is 2 m.
According to the question,
Fifth floor is level sixth floor since the ground floor is level one.
\sf =\dfrac{15}{6} \times 5=12.5 \ m=
6
15
×5=12.5 m
Therefore, the height of the fifth floor is 12.5 m.
Answered by
13
Given :-
Pressure in water pipe at the ground floor = 1.5 × 10⁵ Pa
Pressure in water pipe on the fifth floor = 2 × 10⁴ Pa
To Find :-
The height of the fifth floor.
Analysis :-
Firstly find the height of the building by substituting the given values in the question.
Then you can easily find the height of the fifth floor using the formula of pressure exerted accordingly.
Solution :-
We know that,
p = Pressure
d = Density
g = Gravity
h = Height
Using the formula,
\underline{\boxed{\sf Pressure=Height \times Density \times Gravity}}
Pressure=Height×Density×Gravity
Given that,
Pressure (p) = 1.5 × 10⁵ Pa
Density (d) = 1000 kg/m³
Gravity (g) = 10 m/s
Substituting their values,
\sf 1.5 \times 10^5=h \times 1000 \times 101.5×10
5
=h×1000×10
\sf h=\dfrac{1.5 \times 10^5}{10 \times 1000}h=
10×1000
1.5×10
5
\sf h=5 \ mh=5 m
Therefore, the height of the building is 15 m.
Using the formula,
\underline{\boxed{\sf Pressure=Height \times Density \times Gravity}}
Pressure=Height×Density×Gravity
Given that,
Pressure (p) = 2 × 10⁵ Pa
Density (d) = 1000 kg/m³
Gravity (g) = 10 m/s
Substituting their values,
\sf 2 \times 10^4=h \times 1000 \times 102×10
4
=h×1000×10
\sf h=\dfrac{2 \times 10^4}{10 \times 1000}h=
10×1000
2×10
4
\sf h=2 \ mh=2 m
Therefore, the height from the tank is 2 m.
According to the question,
Fifth floor is level sixth floor since the ground floor is level one.
\sf =\dfrac{15}{6} \times 5=12.5 \ m=
6
15
×5=12.5 m
Therefore, the height of the fifth floor is 12.5 m.The pressure in water pipe at the ground floor of a building is 1.5 x 105 Pa, whereas the pressure on fifth floor is 2 x 104 Pa. Calculate the height of the fifth floor. (Take g = 10 ms-2)
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