Question

the pressure of a gas in a cylinder when it is heated to a temperature 250k is 1.5 atm.what was the initial temperature of the gas if its initial pressure was 1 atm​

Answer 1

Answer:

Please see below

Explanation:

Use Gay Lussac's Formula here. His formula is as follows:

P1/T1 = P2/T2 where P and T stand for pressure (in atm) and temperature (in Kelvins) respectively

Plug in your knowns into the formula and solve for T1, since that's the only value that you're missing and trying to find.

1 atm/T1 = 1.5 atm/250 K

Cross multiply.

250 K * atm = 1.5 atm (T1)

(250 K * atm) / 1.5 atm = T1

From here all you have to do is find out T1 and beware of significant digits