the pressure of a gas is doubled and the temperature is raised to 273K.what is the final volume?
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Answer:
Suppose the volume at STP to be V and pressure to be P and temperature to be T
Now, the number of moles of the gas X present
n=
RT
PV
PV=nRT
Now, the second condition
P
2
=2P
T
2
=3T
Now, the volume
V
2
=
P
2
nRT
2
Now, substituting the value of T
2
and P
2
V
2
=
P
2
nRT
2
V
2
=
T
PV
×
2P
3T
V
2
=
2
3
V
V
2
=1.5V
So, the final volume will be 1.5 fold the original volume.
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