Physics, asked by shashwat523, 1 year ago

the pressure of a liquid of density 1g/cm^3at a depth2cm from the surface of liquid is (atmospheric pressure=1Multiply 10^5and g = 10 m /s^2

Answers

Answered by ishantgoyal23
1
hey
here is your answer
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pressure=height*density*g+ atmospheric pressure
=>0.02*1000*10+1*10^5
=2*10^2+1*10^5
=>(2+1000)10^2
=>1002*10^2
====================
hope it helps
plz mark it as brainliest

shashwat523: ans is 1.002*10^5
shashwat523: sorry u r righy
ishantgoyal23: it is same thing bro
ishantgoyal23: hmm its okk
shashwat523: ishan pls answer my question
ishantgoyal23: which one
shashwat523: I have marked u as brainlist
ishantgoyal23: thnx
shashwat523: hey ishan can u ask a question
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