Question

The pressure of air in a volleyball is 1.30 atm on a day when the temperature is 27 °c (3.00 x 102k). assuming that the number of moles of air and the volume of the ball do not change, then what is the pressure of the air in the volleyball if the temperature falls to 15 °c (288 k)? pressure: atm

Answer 1

Given:

The volume of volleyball remains constant.

Initial Pressure, P1 = 1.30 atm

Initial Temperature, T1 = 27 °C = 300 K

Final Temperature, T2 = 15 °C = 288 K

To Find:

The final pressure of the air in the volleyball.

Calculation:

- Using Gay Lussac's law, we have:

P1/T1 = P2/T2

⇒ P2 = P1T2/T1

⇒ P2 = 1.30 × 288/300

⇒ P2 = 1.248 atm

- So, the pressure of the air in the volleyball if the temperature falls to 15 °c (288 k) is 1.248 atm.