The price list of electronic items in a shop is shown below. item1 is cell phone and item2 is camera ,the marked price of cellphone is 4000,discount is 15% .The marked price of camera is 11000 ,discount is 10%.
Nikhil bought 2 cellphones and 1 camera.How much money should he pay after discount?
Answers
Answered by
0
Discounted price of 1 cellphone = 85% of 4000
= ₹ 3400
Discounted price of 1 camera = 90% of 11000
= 9900
Therefore total cost will be equal to {(2 × 3400) + 9900}
={6800 + 9900}
= ₹ 16700
Plz mark as brainliest
= ₹ 3400
Discounted price of 1 camera = 90% of 11000
= 9900
Therefore total cost will be equal to {(2 × 3400) + 9900}
={6800 + 9900}
= ₹ 16700
Plz mark as brainliest
Answered by
1
1)marked price cell phone =M = Rs 4000
discount =d=15%
selling price = sp = m(100-d)/100
= 4000(100-15)/100
=40 *85
=Rs 3400
2) marked price of camera =M = Rs 11000
d= 10%
sp = 11000(100-10)/100
= 110*90
=Rs 9900
therefore he has to pay = 2* cell phone sp +camera sp
= 2*3400 +9900
=6800+9900
=Rs16700
discount =d=15%
selling price = sp = m(100-d)/100
= 4000(100-15)/100
=40 *85
=Rs 3400
2) marked price of camera =M = Rs 11000
d= 10%
sp = 11000(100-10)/100
= 110*90
=Rs 9900
therefore he has to pay = 2* cell phone sp +camera sp
= 2*3400 +9900
=6800+9900
=Rs16700
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