The price of 3 table and 5 chairs is ₹ 7050 but a table costs ₹ 150 more than a chair find the price of each
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Answered by
11
Hi friend!!
Let the cost of the table =x
Let the cost of the chair=y
Given,
The price of 3 table and 5 chairs is ₹ 7050
=3x+5y=7050----(1)
It is also given that
a table costs ₹ 150 more than a chair
→x=y+150
substituting in (1), we get
3(y+150)+5y=7050
3y+450+5y=7050
8y=6600
y=825
→x=y+150=825+150=975
Cost of a table is 975
Cost of a chair=825
I hope this will help you ;)
Let the cost of the table =x
Let the cost of the chair=y
Given,
The price of 3 table and 5 chairs is ₹ 7050
=3x+5y=7050----(1)
It is also given that
a table costs ₹ 150 more than a chair
→x=y+150
substituting in (1), we get
3(y+150)+5y=7050
3y+450+5y=7050
8y=6600
y=825
→x=y+150=825+150=975
Cost of a table is 975
Cost of a chair=825
I hope this will help you ;)
Answered by
6
Heya....☺
_______________________
Here's ur ans. ⬇
◾ Let the cost of chair be y
◾ Let the cost of table be x
Then ,
According to question
3x + 5y = 7050 ... 1st equation
x = 150 + y ... 2nd equation
Substituting, the value of x in 1st equation
3(150 + y) + 5y = 7050
450 + 3y + 5y = 7050
8y = 7050 - 450
y = 6600 / 8
y = 825
Then,
x = 150 + 825 = 975
Therefore ,
cost of chair = Rs. 825
cost of table = Rs . 975
_________________
✌,Hope it helps
_______________________
Here's ur ans. ⬇
◾ Let the cost of chair be y
◾ Let the cost of table be x
Then ,
According to question
3x + 5y = 7050 ... 1st equation
x = 150 + y ... 2nd equation
Substituting, the value of x in 1st equation
3(150 + y) + 5y = 7050
450 + 3y + 5y = 7050
8y = 7050 - 450
y = 6600 / 8
y = 825
Then,
x = 150 + 825 = 975
Therefore ,
cost of chair = Rs. 825
cost of table = Rs . 975
_________________
✌,Hope it helps
Anonymous:
nice
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