Math, asked by Punarvas4622, 11 months ago

The price of a table is Rs. 400 more than that of a chair. If 6 tables and 6 chairs together cost Rs. 4800, by
what percent is the price of the chair less than that of the table?

Answers

Answered by aneekethn
6

Answer:

300%

Step-by-step explanation:

First, we have to write down the given points.

Let the table be 'x' and chair be 'y'.

Price of a table is $400 more than that of a chair.

So, x= y+400.

If 6 chairs and 6 tables cost $4800,

12y+ $2400=$4800

12y=$4800-$2400

12y=$2400

y=$2400/12

y=200

Cost of a chair= $200

Cost of a table=$600

Percentage= 600/200 x 100%

=300%

Answered by sspriya9499
0

Answer:

let us consider price of a chair = x

price of a table= x+400

given: 6 chairs + 6 tables = 4800

6x +6(x+400)= 4800

6x+6x+2400= 4800

12x= 4800-2400

x= 2400/12

x= 200

therefore ,price of chair = 200

price of table = x+400=200+400= 600

required % = 200 /600 ×100

= 100/3

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