Question

The price of a watch ist 50 more than twice the price of a gold ring. Let the price of the ring be x. (i) Express the price of the watch in terms of x. (ii) If the price of the watch is 208, find the price of the ring

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Answer 1

Step-by-step explanation:

let the price of ring =x

i) price of watch= 50+ 2x

ii) price of watch =208

then 50+2x =208. ( using (i))

2x=208-50= 158

x= 158/2

x= 79

so,price of ring =79

Answer 2

(i)

As, ring's price is x,

Price of watch would be 50 more than twice of gold ring's price, i.e

2x + 50

therefore, price of gold watch in terms of x would be (2x+ 5)

(ii)

Price of the watch is (2x + 5)

Also, it is mentioned that its price is Rs 208

So, we got an equation to compute, i.e

$2x \: + 50 \: = \: 208 \\ 2x \: = \: 208 - 50 \\ 2x \: = \: 158 \\ x \: = \: \frac{158}{2} \\ \\ x \: = \: 79$

∵ x = 79,

→ we got the price of gold ring as

Rs 79

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