Math, asked by yosantsegai256, 9 months ago

The price of a watch was increased by 10% to £132. What was the price before the increase?

Answers

Answered by Latoyastar246
55

Answer:

120

Step-by-step explanation:

so what you do is the new answer which is 132 divided by the multiplier which is 100%+10%=110=1.1

so you do 132 divided by 1.1=120

I PROMISE THIS IS 100% THE RIGHT ANSWER

Answered by Anonymous
1

Given - New price

Find - Original price

Solution - Let the original price be x. Forming the equation for given information -

x + 10% of x = 132

x + 10x/100 = 132

Taking LCM, we get 100

 \frac{100x + 10x}{100}  = 132

Performing addition and shifting 100 to Right Hand Side

110x = 132*100

Performing multiplication

110x = 13200

Shifting 110 to Right Hand Side

x = 13200/110

Performing division

x = 120

Hence, the price before the increase was £120.

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